0.01x^2+.30x-97.75=0

Solution for 0.01x^2+.30x-97.75=0 equation:

0.01x^2+.30x-97.75=0

a = 0.01; b = .30; c = -97.75;
Δ = b2-4ac
Δ = .302-4·0.01·(-97.75)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.30)-2}{2*0.01}=\frac{-2.3}{0.02}
=-114+0.02/0.02
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.30)+2}{2*0.01}=\frac{1.7}{0.02}
=85
$